Twirlnhurl
Well-Known Member
There are currently 11 daily flights from Orlando to Miami, 6 daily flights from Orlando to Fort Lauderdale, and zero flights from Orlando to West Palm Beach. Assuming those flights have 200 passengers each (a generous assumption), that is 3,400 one way passengers from Orlando to South Florida per day.Trains are an interesting curiosity and they have a fan base. However they are really not needed in the USA. Long trips are better served by aircraft while buses work better for short trips. Trains are anachronistic blivits in the world of transportation.
In October 2023, the Brightline train served 79,686 passengers between Orlando and South Florida (source), an average of 2,571 passengers a day.
Note that the reported Brightline trips may be in both directions, the article makes it sound like it is one way, but I think that may be wrong. If that is the case, the correct one way daily ridership may be 1,285.
Regardless, the share of train passengers is either 43% or 27% of the total non-road trips between Orlando and South Florida.
That is a significant share of trips!
If there can only be one mode of travel between the two, train probably wouldn't be the best choice for the most people. But, there can be more than one mode, and what is best for one person isn't necessarily the best for someone else.
If you were to take an average square mile of the United States, it is unlikely that rail is the best mode of transportation for that square mile. But there are many, many square miles in this country where rail has significant advantages over other modes. Just ask anyone trying to drive to Orlando from Miami on a Friday at 5:00 pm. The last time I did it, it took 75 minutes to go from the Miami airport to the turnpike (14 miles). Does a train really have no advantage over a car or bus when the highways are that congested?
Trains don't need to be the best mode for all users to be useful to use users. And there are some users for some trips where train is objectively better than all alternatives.
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