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- Thread starter SpongeScott
- Start date
shuflemstr
Well-Known Member
Oh my gosh. I can't believe it. I really want to know how this works too.
How did it know!? 
tiggerlover1971
New Member
dang that was neat
ok, how did YOU do that then?
wdwhoneymooner
Well-Known Member
Jedi Mind Trick?
*I feel like drinking Sprite.........*
*I feel like drinking Sprite.........*
garyhoov
Trophy Husband
I can see the logic. With some time and thought (which I'm not going to spend), I think I could produce the algorithm.
Consider a number: wxyz
Now rearrange the digits: zwxy
You have four variables and quite a bit of information. Assume all the digits in the first number are greater than all the digits of the second (if they're not, it adds an extra dimension to the equation, but it's managable) Now assume your final answer is something like 2156. You take out the 1.
The computer now knows that w-z = 2 (it doesn't necessarily know that it's dealing with w and z but there are only four digits so the options are limited. w might be 8 and z might be 6 or w might be 4 and z might be 2, but again you see, the options are limited.
y - x = 5, so you can see this is even more limiting. y might be 8 and x 3, but x can't be greater 4 (see my original simplification).
The key is there are only 4 digits and a limited number of possibilities. With a lot of time, and a lot of paper, you could, by simple trial and error, figure out a friend's number. With the calculating ability of the computer, I'm sure it's quite simple.
Consider a number: wxyz
Now rearrange the digits: zwxy
You have four variables and quite a bit of information. Assume all the digits in the first number are greater than all the digits of the second (if they're not, it adds an extra dimension to the equation, but it's managable) Now assume your final answer is something like 2156. You take out the 1.
The computer now knows that w-z = 2 (it doesn't necessarily know that it's dealing with w and z but there are only four digits so the options are limited. w might be 8 and z might be 6 or w might be 4 and z might be 2, but again you see, the options are limited.
y - x = 5, so you can see this is even more limiting. y might be 8 and x 3, but x can't be greater 4 (see my original simplification).
The key is there are only 4 digits and a limited number of possibilities. With a lot of time, and a lot of paper, you could, by simple trial and error, figure out a friend's number. With the calculating ability of the computer, I'm sure it's quite simple.
But I knew if someone could figure it out, it would be him.
tenchu
Well-Known Member
Good shout bud.
And it of course only works if the numbers in your oringinal are not all the same, if you try to fool it and use the same number 4 times (e.g. 1111) you end up with 0 when you subtract it from the re-combinated one.
Hence why they've had to put the 'different numbers' bit in.
I was too busy looking for loopholes to make it wrong rather than woring out how to make it work! :lol:
garyhoov
Trophy Husband
:lol: I think that's why I never really enjoyed Disney World as a kid. I used to just think: "That looks so fake"
Now that I'm older and wiser, I can simply marvel and say: "Wow . . .
I wonder what kind of servo actuation they would use to synchronize that movement." Now where's that geek smiley when you really need it?
WDWFREAK53
Well-Known Member
Gary...I figured that out...Sheesh...that was simple...I just didn't want to look like a nerdo maxo dweebie :lookaroun
MouseMadness
Well-Known Member
Gary, can you help Kaitlyn with her homework? :lookaroun
wdwhoneymooner
Well-Known Member
Gary = Yoda
mkepcotmgmak
Well-Known Member
WDWFREAK53
Well-Known Member
...this one has even me baffled...
or maybe all the cards are different anyways? Nahhh